Question

In C code prompt and read from the user an integer number, 'N', of double precision floating point numbers to allocate for the purpose of the current test run. Dynamically allocate an array of N double precision floating point numbers; i.e. the array will require "N*sizeof(double)" bytes of RAM for storage, call this M.

Answer 1

#include <stdio.h>
#include <malloc.h>

int main() {
    int i, N;
    double *M;
    printf("How many doubles? ");
    scanf("%d", &N);
    M = malloc(N*sizeof(double));
    printf("Enter %d double precision numbers: ", N);
    for (i = 0; i < N; ++i) {
        scanf("%lf", M+i);
    }

    printf("You entered: ");
    for (i = 0; i < N; ++i) {
        printf("%lf ", M[i]);
    }
    printf("\n");
    free(M);
    return 0;
}