If 18.0 g of NaF (40 g/mol) and 32.0 g of HF (20 g/mol) are dissolved in water to make 750 mL of solution, what will the pH be?
For HF, Ka = 6.8 x 10^-4
A. 3.17
B. 3.74
C. 3.47
D. 2.62
E. -0.57
Need answer asap
If 18.0 g of NaF (40 g/mol) and 32.0 g of HF (20 g/mol) are dissolved...
Calculate the pH of a buffer solution prepared by dissolving 1.79 mol of HF and 2.26 mol of NaF in water to make a total volume of 1.25 L of solution. The Ka of HF is 6.8*10^-4. A) 3.57 B) 3.47 C) 3.27 D) 3.37 E) 3.68 Please let me know what answer is correct and how to work it. Thank You!
How many moles of HCl need to be added to 200.0 mL of a 0.200 M solution of NaF to make a buffer with a pH of 3.60? (Ka for HF is 6.8 x 10-4)
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Question 26 of 31 Sub How many moles of HCl need to be added to 200.0 mL of a 0.200 M solution of Naf to make a buffer with a pH of 3.60? (ka for HF is 6.8 * 10-4) mol
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How many moles of HCl need to be added to 200.0 mL of a 0.200 M solution of NaF to make a buffer with a pH of 3.60? (Ka for HF is 6.8 x 10-4)
The molar mass of hydrogen fluoride, HF, is 20.00 g/mol. If 17.0 grams of HF are dissolved in water to give 200.0 mL solution, what is the molaroty of this solution?