What is the molar solubility of AgCl in 0.10 M NH3? K sp for AgCl is 1.8×10-10 and K f for Ag(NH3)2+ is 1.7×107
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5.5 × 10-3 M |
3.9 × 10-3 M |
1.3 × 10-5 M |
5.5 × 10-2 M |
What is the molar solubility of AgCl in 0.10 M NH3? K sp for AgCl is...
Question 10 What is the molar solubility of AgCl in 0.10 M NH3? The K for dissolution of AgCl in NHą is 3.06 x 103 O 5.5 x 10-2M o 1.3 x 10-5M O 5.0 x 10-3M 5.5 x 10-3M
TA What is the molar solubility of AgCl in 0.50 M NH3? Ksp for AgCl is 1.8x10-10 and K for Ag(NH3)2 + is 1.7x107 ANSWER: 1.3 x 10-5 M 2.0 x 10-2 M 5.5 x 10-2 M 5.8 x 10-2 M
Part A What is the molar solubility of AgCl in 0.20 M NHg? Kop for AgCl is 1.8 * 10-10 and Kfor Ag(NH3)2 * is 1.7 * 10%. O 5.5 x 10-2M O 1.1 x 102M 1.0 x 102 M 1.3 x 10-M Submit Request Answer ovide Feedback
What is the molar solubility of AgCl in 0.10M NH3? Ksp=1.8*10^-5 and kf (Ag(NH3)2)=1.7*10^7
What is the molar solubility of AgCl (Ksp = 1.80 x 10-10) in 0.330 M NH3? (Kf of Ag(NH3)2* is 1 x 107) IM What is the equilibrium constant for the solubility of FeCO3 (Ksp = 2.1 x 10-11) in NaCN? (Kf of Fe(CN)64-is 1.0 x 1035)
What is the solubility of AgCl in pure water at 25°C? The Ksp of AgCl is 1.8x10^-10. 9.0 x 10^-11 1.3 x 10^-5 1.8 x 10^-3 3.6 x 10^-10 What is the solubility of AgCl in 10 M NH3? The Kf of Ag(NH3)2+ from AgCl(s) in aqueous NH3 is 0.0031, which is for the balanced reaction shown below. AgCl(s) + 2 NH3(aq) → Ag(NH3)2+(aq) + Cl-(aq) Kf = 0.0031 0.176 M 0.426 M 0.023 M 0.557 M
4) Calculate the molar solubility of AgCl (Ksp = 1.8 x 10-) at 25°C in: (a) Pure water (b) 3.0 M NH3 [Hint: AgCl(s) + 2NH3(aq) Ag(NH3)2(aq) + Cl(aq) K = 3.1 x 10
Calculate the molar solubility of thallium(I) chloride in 0.20 M NaCl at 25°C. K sp for TlCl is 1.7 × 10 -4. 1.3 × 10-2 M 8.5 × 10-4 M 5.8 × 10-3 M 3.4 × 10-5 M
26. Kę for the complex ion Ag(NH3)2 + is 1.7 x 10”. Ksp for AgCl is 1.6 x 10-10. Calculate the molar solubility of AgCl in 0.70 M NH3. Solubility =
Question 18 of 21 What is the molar solubility of AgCl (Ksp = 1.80 x 10^º) in 0.620 M NH3? (Kf of Ag(NH3)2* is 1 x 10) | 1 2 3 +/- 0 x 100