Fill in the P(X=x)
values in the table below to give a legitimate probability distribution for the discrete random variable X, whose possible values are
1,3,4,5, and 6
Value x of X |
P (X=x) |
1 |
|
3 |
|
4 |
0.28 |
5 |
0.15 |
6 |
0.23 |
Answer )
We know that sum of all the probabilities is equal to 1
Let the probability for 1 and 3 be x and y respectively
X + y + 0.28 + 0.15 + 0.23 = 1
X + Y = 1 - (0.28 + 0.15 + 0.23)
X + Y = 0.34
So, two possible values are 0.17 + 0.17 = 0.34
X = 0.17
Y = 0.17
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