Find the probability a randomly selected z-score is between -1.4 and 2.3.
A) 0.9085
B) 0.0564
C) 0.8769
D) 0.9192
Solution :
Given that,
Using standard normal table ,
P(-1.4 < z < 2.3)
= P(z < 2.3) - P(z < -1.4)
= 0.9893 - 0.0808
= 0.9085
P(-1.4 < z < 2.3) = 0.9085
option A) is correct
Find the probability a randomly selected z-score is between -1.4 and 2.3. A) 0.9085 B) 0.0564...
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