How large a sample n would you need to estimate p with margin of error 0.04 with 90% confidence? Assume that you don’t know anything about the value of p.
a. n = 601
b. n = 423
c. n = 1068
d. n = 608
e. n = 2305
Solution :
Given that,
= 1 - = 0.5
margin of error = E = 0.04
Z/2 = 1.645
sample size = n = (Z / 2 / E )2 * * (1 - )
= (1.645 / 0.04)2 * 0.5 * 0.5
= 423
sample size = n = 423
option b. is correct
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