Do the titration on Unknown 6 (results are a pH of 13.75 after titration) Give the:...
Do the titration on Unknown 6 (results are a pH of 13.75 after titration)
Give the:
3 letter abbreviation of the amino acid
pka1 (COOH) value?
pka2 (NH3+) value?
pka3 (side chain) value?
pI value?
The only info given is the ph that is 13.75 and 34 ml of titrant was used.
Homework Answers
Since the pH of the solution is 13.75 after titration, it indicates that base has been used to titrate the solution and after titration, the resulting pH has come because of addition of some extra base.
Now among the amino acids, arginine which has the following structure has pKa3 at 12.48. Hence for the titration fo this amino acid, high concentration of base will be required. Therefore the possible amino acid is arginine.
The pKa1 for this is 2.17, the pka2 is 9.04 and pka3 is 12.48. This is known from literature.
Add Answer to:
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IN CLER HAND WRITING PLEASE HELP AND ANSWER AS SOON AS
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1- where the pKas are located (for pKa1, pKa2 and if
applicable, pKa3) for your unknown.
2-write their values on the correct parts of the graph. c)
mark where the buffering regions are.
3-Record the pKa values below, that you obtained from the
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I have attached a titration of a mock amino acid with OH-. I
have labeled the different charge states of the amino acid as I,
II, III, IV. I have labeled different points on the titration curve
as A, B, ....G. I want you to tell me which form(s) of the species
I, II, III or IV predominates (is present at greatest
concentration) at each of the lettered points on the curve. I would
also like you to calculate the...
it's a bio-chem problem.
"I have attached a titration of a mock amino acid with OH-. I
have labeled the different charge states of the amino acid as I,
II, III, IV. I have labeled different points on the titration curve
as A, B,...G. I want you to tell me which form(s) of the species
I,II,III,IV predominates (is present at greatest concentration) at
each of the lettered points on the curve. I would also like you to
calculate the PI...
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