A Gold-201 decays due to alpha emission. What would the expected outcome be? Why?
Atomic number of gold (Au) is 79. Gold -201 can be represented as .
Alpha emission involves removal of a helium nucleus
So if gold-201 decays by alpha emission we hva ethe following reaction
The resulting atom formed will be Iridium (Ir) with atomic number 77 and mass number 197. This is because 201-4=197 (subtraction of mass number of alpha particle from mass number of gold) and 79-2=77 (subtraction of atomic number of alpha particle from atomic number of gold) and 77 is the atomic number of Iridium (Ir).
A Gold-201 decays due to alpha emission. What would the expected outcome be? Why?
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