Use technology to find the P-value for the hypothesis test described below.
The claim is that for 12 AM body temperatures, the mean is μ<98.6°F. The sample size is n=33 and the test statistic is t= - 2.515
P-value=??????
Solution:
Given that,
This is a left tailed test.
n = 33
df = n - 1 = 33 - 1 = 32
t = -2.515
Then,
p-value = 0.0086
The p-value is 0.0086
Using a t-distribution table or a calculator, the P-value for a two-tailed test with a test statistic of t = -2.515 and degrees of freedom (df) = 32 (n-1) is approximately 0.0179.
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