Question

Can you write the following code without using any logical operators?

cout << “Are you hungry? (0-no, 1, yes) << endl;

cin >> choice;

if(choice == 1 && store == OPEN) { //get some food from the store

} else if(choice == 1 && store == CLOSED) {

//make some food at home

}

else { //I’m not hungry }

Answer 1

For the following C++ program, to make it run without using any conditional statements, we make use of a 2D array of strings named ans[2][2].

This array will contain all possible outcomes for values entered by the user for hungry and store. So every time, regardless of the user input ans[choice][store] will be printed.

So, if user is hungry(1) and store is closed(0) then ans[1][0] will be printed, if he is hungry(1) and store is open(1), then ans[0][1] will be printed and so on...

CODE:

#include <iostream>

using namespace std;

int main()
{
int store,choice;
//string array for all possible answers:
string ans[2][2]={ "make some food at home","make some food at home",
"get some food from the store", "make some food at home"};
cout << "Are you hungry? (0-no, 1-yes)" << endl;
cin >> choice;
cout<<"Is store open?(0-closed, 1-open)"<<endl;
cin>>store;
cout<<ans[choice][store]; //printing the answer

return 0;
}

OUTPUT: