Question

Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance.

Summary Table for Divorces
AVERAGE	1,487
MEDIAN	1,118
STANDARD DEVIATION	1528.92805
MAX	7,627
MIN	71

1. Clearly state a null and alternative hypothesis
2. Give the value of the test statistic n=52
3. Report the P-Value
4. Clearly state your conclusion (Reject the Null or Fail to Reject the Null)
5. Explain what your conclusion means in context of the data.

Answer 1

Answer:

a)

Given,

Ho : u > 4000

Ha : u <= 4000

b)

test statistic z = (x - u)/(s/sqrt(n))

= (1487 - 4000)/(1528.92805/sqrt(52))

z = -11.85

c)

P(z > -11.85) = 0 [since from z table]

= 0

d)

Here p value < 0.05 alpha, so we reject Ho.

So we have sufficient evidence.