Biochemistry II: Calculating ATP from beta-oxidation
In calculating the number of ATP molecules generated by the beta-oxidation of a single fatty acid molecule with an even number of carbons,
a) Identify how the P/O ratios can be used (what are their significance),
and b) help me to construct a formula given the P/O value of 3 for NADH and 2 for FADH2.
Calculating ATP from beta-oxidation:
answer:
- oxidation: It is defined as the metabolic process which involves fatty acids are broken down into produce energy
i. Palmitoyl-coA + 7CoA + 7 FAD + 7 NAD+ + 7 H20 -------------> 8 acetyl coA + 7 FADH2 + 7 NADH + 7H+
ii. 8 Acetyl coA + 16 02 + 96 Pi + 96 ADP -------------------> 8 coA + 96 ATP + 104 H20 + 16 C02
iii. Overall reaction:
Palmitoyl-coA + 23 02 + 131 Pi + 131 ADP -----------------> coA + 131 ATP + 16 C02 + 146 H20
yield of ATP during one molecule palmitoyl-coA to C02 to H20
S.no. | Enzyme catalyzing oxidation steps | Number of NADH2 or FADH2 formed | number of ATP formed |
1. | Acy-coA dehydrogenase | 7 FADH2 | 14 |
2. |
Hydroxyacyl coA dehyrogenase |
7 NADH | 21 |
3. | Isocitrate dehydrogenase | 8 NADH | 24 |
4. | ketoglutarate dehydrogenase | 8 NADH | 24 |
5. | Succinyl-CoA synthetase | 8 | |
6. | Succinate dehydrogenase | 8 FADH2 | 16 |
7. | Malate dehydrogenase | 8 NADH | 24 |
Total = | 131 |
Total = 131 ATP
for activation of palmitate to palmitoyl-coA = 2 ATP consumed
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129 ATP
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a) Identify how the P/O ratios can be used
b) construct formula given P/O value 3 for NADH and 2 FADH2
answer:
P/O ratio or phosphate / oxygen ratio refers to the amount of ATP produced from transfer of electron through ETC
Each FADH2 yields 1.5 ATPs and each NADH yields 2.5 ATPs
Beta oxidation (7 turns)
1 NADH per turn X 7 turns X 2.5 (P/O ratio) = 17.5 ATP
1 FADH2 per turn X 8 turns X 1.5 (P/O ratio) = 10.5 ATP
For TCA cycle (8 turns):
3 NADH per turn X 8 turn X 2.5 = 60 ATP
1 FADH2 per turn X 8 turn X 1.5 = 12 ATP
1 GTP /ATP per turn X 8 turn = 8 ATP
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Total = 108 ATP - 2 ATP ( for activation of fatty acid) = 106 ATP
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