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In an X-ray tube, a uniform electric field E extends over a distance of 12 cm...

In an X-ray tube, a uniform electric field E extends over a distance of 12 cm from an electron source to a target; the field points from the target to the source. If the potential difference between the source and target is 40 kV then what is the magnitude of the electric field? What is the energy gained by an electron as it accelerates from source to target? Express the energy both in electronvolts and joules.

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