An object traverses a pipe with a velocity that obeys the following dependence on time, ! v =αt 2 + βt , where the velocity is measured in m/s and the time, t, in seconds. α and β are constants, α = −5⋅107 ,β = 3⋅105 . The acceleration of the object just as it leaves the pipe is zero.
(a) What are the units of the constants α and β? Rewrite the velocity expression using the values of these constants and their appropriate units.
(b) Derive expressions for the acceleration and position of the object as a function of time when the object is in the pipe. Please make sure to include the appropriate units of the coefficients that show up in your derived expressions.
(c) Calculate the time it takes the object to cross the pipe, and its speed as it exits the pipe.
(d) Determine the length of the pipe.
An object traverses a pipe with a velocity that obeys the following dependence on time, !...
an objects velocity as a function of time is given by v(t)=bt-ct^3, where b and c are positive constants with appropriate units. if the object starts at x=0 at the time t=0, find expressions for a) the time when its again at x=0 and b) its acceleration at that time.
Following figure shows velocity -time graph of an object. a) Sketch the acceleration-time graph that correspond to this motion. b) Assuming the initial position is zero, determine the displacement of the object from beginning to t=8.0 seconds after it starts.
Consider an object moving along a line with the following
velocity and initial position. Assume time t is measured in seconds
and velocities have units of m/s. Complete parts (a) through (d)
below.
Consider an object moving along a line with the following velocity and initial position. Assume time t is measured in seconds and velocities have units of m/s. Complete parts (a) through (d) below. v(t) = -1-2cos for Osts (0) = 0 (**). a. Over the given interval,...
Vibrational Motion Introduction If an object is following Hooke’s Law, then Fnet = -kx = ma Since acceleration is the second derivative of position with respect to time, the relationship can be written as the differential equation: kx = m δ2xδt2/{"version":"1.1","math":"<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>k</mi><mi>x</mi><mo> </mo><mo>=</mo><mo> </mo><mi>m</mi><mo> </mo><mfrac bevelled="true"><mrow><msup><mi>δ</mi><mn>2</mn></msup><mi>x</mi></mrow><mrow><mi>δ</mi><msup><mi>t</mi><mn>2</mn></msup></mrow></mfrac></math>"} Methods for solving differential equations are beyond the scope of this course; in fact, a class in differential equations is usually a requirement for a degree in engineering or physics. However, the solution to this particular differential...