X-rays with a wavelength of 1.34 Å scatter at an angle of 29.0 ∘ from a...
X-rays with a wavelength of 1.34 Å scatter at an angle of 29.0 ∘
from a crystal.
If n=1, what is the distance between planes of atoms in
the crystal that give rise to this scattering?
Homework Answers
From Bragg's law n
= 2d
sin
Where
n= 1
= wave length
of X-rays= 1.34 Ao= 1.34*10^-10 m
= scattering
angle= 29.0o
d= distance between the planes=?
Substitute the above values we get d= 1.38*10^-10 m
d=1.38 Ao
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