What is the probability that for a randomly chosen natural number k, there is a Fibonacci number between 2k and 3k?
FIbonacci nomber of 18 is 1597
FIbonacci nomber of 19 is 2584
FIbonacci nomber of 20 is 4181
means only one febonacci number present in 2k to 3k.
So p=1.0 (100% chance ) probabilty to select randomly choosen natura number k..
thank you...
What is the probability that for a randomly chosen natural number k, there is a Fibonacci...
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