Question

IP The artery in the figure has an inside diameter of 2.75 mm and passes through a region where the magnetic field is 0.069 T . If the voltage difference between the electrodes is 199 μV , what is the speed of the blood (to 2 significant figures)?

A 6.70 −μC particle moves through a region of space where an electric field of magnitude 1500 N/C points in the positive x direction, and a magnetic field of magnitude 1.24 T points in the positive z direction. If the net force acting on the particle is 6.24×10⁻³ N in the positive x direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane.

Answer 1

a)

considering hall effect

V = B r V

199* 10^-6 = 0.069* 2.75 / 2* 10^-3* v

v = 2.1 m/s

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b)

considering equilibrium of forces

F = qE + qBv

F - qE = q Bv

v = ( 6.24* 10^-3 - 6.7* 10^-6* 1500) / ( 6.7* 10^-6* 1.24)

v = 458.594 so

components of velocity

vx = 0 m/s

vy = - 458.594 m/s

vz = 0 m/s

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