1. How many GRAMS of ammonium phosphate, (NH4)3PO4, are present in 2.81×1022 formula units of this...

Question

Question

1. How many GRAMS of ammonium phosphate, (NH4)3PO4, are present in 2.81×1022 formula units of this compound?

Answer 1

Answer #1

We know that

Moles = no of molecules /Avagadro no

Moles = 2.81x10²² /6.022x10²³

Moles = 0.0466

Now moles = weight /molecular weight

But moles, 0.0466= wt/149

Therefore weight = 6.951 gm

Answer 2

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