if you have 2.60x10^23 molecules of (NH4)3PO4 how many grams to you have

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if you have 2.60x10^23 molecules of (NH4)3PO4 how many grams to you have

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Answer 1

Answer #1

According to this paoblema we have to apply this formisla - n= NA Whege n= no. of moles N = Number of molecules NA = Avogadao whese, n=no. of mole compound .. of the m = mass of that compound M = Molar mass of that compound As we know that Molas mass

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if you have 2.60x10^23 molecules of (NH4)3PO4 how many grams to you have

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1. How many GRAMS of ammonium phosphate, (NH4)3PO4, are present in 2.81×1022 formula units of this...

How many moles of nitrogen atoms and hydrogen atoms are present in 1.4 moles of (NH4)3PO4?

23. How many molecules of carbon monoxide, CO, comprise 4.82 grams?

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if you have 2.60x10^23 molecules of (NH4)3PO4 how many grams to you have

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