Identify the three stereoisomers of the hydrobenzoin product using R and S descriptors. If there are three isomers, why are there only two product lines in the prelab table?
compound |
mol. wt. (g/mol) |
mmol |
amount (g) (mL) |
m.p. (˚C) |
density (g/mL) |
ref. |
|
benzil |
210.23 |
2.38 mmol |
.5g |
- |
94-95 °C (lit.) |
1.23 g/mL |
|
sodium borohydride |
37.832 g/mol |
2.64 mmol |
.1g |
- |
400°C |
1.375 g/mL |
|
ethanol |
46.07 g/mol |
- |
- |
5 mL |
- |
0.789 g/mL |
|
meso-hydrobenzoin |
214.26 g/mol |
2.38 mmol |
.509g |
- |
137-139 °C (lit.) |
1.193 g/mL |
|
(±)-hydrobenzoin |
214.264 g/mol |
2.38 mmol |
.509g |
- |
119-120 °C |
1.0 g/mL |
(+)hydrobenzoin and (-)hydrobenzoin are enantiomers. There all physical properties are same except their behavior with plane polarised light. There properties are same , that's why these two products are being added in same line.
Priority to the groups are based on atomic number, according to C.I.P. rule. Higher atomic number group gets higher priority. 4th priority group should be placed into the plane of paper/board. Connect 1-2-3 , if direction is clockwise it is R otherwise it is S configuration of chiral Carbon.
Identify the three stereoisomers of the hydrobenzoin product using R and S descriptors. If there are...
EXPERIMENT 11 THE MICROSCALE REDUCTION OF BENZIL WITH SODIUM BOROHYDRIDE INTRODUCTION Oxidation-reduction (redox) reactions occur in concert. One substance undergoes oxidation by donating electrons to another substance that is then reduced. In organic chemistry certain rules are followed in determining whether a particular substrate is being oxidized or reduced. Oxidation: The loss of hydrogen and/or gain of oxygen by a substrater Reduction: The gain of hydrogen and/or loss of oxygen by a substrate When an organic substrate is reduced, the...