Delta G for acetic acid dissociation is 27.1 kj/mol. calculate the Ka for acetic acid at 25 degrees C.
Sol.
As Standard change in gibbs free energy = deltaG°
= 27.1 KJ/mol = 27100 J/mol
And , deltaG° = - R × T × ln(Ka)
where R = Gas constant = 8.314 J/ K mol
T = Temperature = 25°C = 298 K
Ka = Acetic acid dissociation constant
So , 27100 = - 8.314 × 298 × ln(Ka)
ln(Ka) = - 10.9381
Therefore , Ka = e-10.9381 = 1.77 × 10-5
Delta G for acetic acid dissociation is 27.1 kj/mol. calculate the Ka for acetic acid at...
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