If the delta G°¢ for ATP hydrolysis is –31 kJ/mol and the delta G°¢ for phosphoenolpyruvate...
If the delta G°¢ for ATP hydrolysis is –31 kJ/mol and the delta G°¢ for phosphoenolpyruvate hydrolysis is –62 kJ/mol, what is the DG°¢ for the phosphorylation of ADP by phosphoenolpyruvate?
A) –93 kJ/mol
B) –31 kJ/mol
C) +31 kJ/mol
D) +93 kJ/mol
E) none of the above
Please provide explanation of how to solve this question, if
possible include the reactions, thank you so much
Homework Answers
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If the delta G°¢ for ATP hydrolysis is –31 kJ/mol and
the delta G°¢ for phosphoenolpyruvate...
If the ΔG°' for ATP hydrolysis is –30 kJ/mol and the ΔG°' for phosphoenolpyruvate hydrolysis is...
If the ΔG°' for ATP hydrolysis is –30 kJ/mol and the ΔG°' for phosphoenolpyruvate hydrolysis is –62 kJ/mol, what is the ΔG°' for the phosphorylation of ADP by phosphoenolpyruvate? a) -32 kJ/mol b) -62 kJ/mol c) +31 kJ/mol d) +92 kJ/mol e) -92 kJ/mol Please provide the appropriate calculation and show the reactions that are involved + the overall reaction. Thank you!
The last step of glycolysis converts phosphoenolpyruvate to pyruvate. phosphoenolpyruvate + ADP " pyruvate + ATP...
The last step of glycolysis converts phosphoenolpyruvate to pyruvate. phosphoenolpyruvate + ADP " pyruvate + ATP A G = -33 kJ/mol (-7.5 kcal/mol) The AG" of the reverse reaction is +31 kJ/mol (+7.5 kcal/mol). Instead of reversing the pyruvate kinase reaction, the step is bypassed in gluconeogenesis. Several steps for the conversion of pyruvate to phosphoenolpyruvate via gluconeogenesis are given. Place the steps in the correct order. You will not place all of the steps. First step
The last step of glycolysis converts phosphoenolpyruvate to pyruvate. phosphoenolpyruvate + ADP - pyruvate + ATP...
The last step of glycolysis converts phosphoenolpyruvate to pyruvate. phosphoenolpyruvate + ADP - pyruvate + ATP A G = -33 kJ/mol (-7.5 kcal/mol) The AG® of the reverse reaction is +31 kJ/mol (+7.5 kcal/mol). Instead of reversing the pyruvate kinase reaction, the step is bypassed in gluconeogenesis. Several steps for the conversion of pyruvate to phosphoenolpyruvate via gluconeogenesis are given. Place the steps in the correct order. You will not place all of the steps. First step Last step Answer...
please help! thanks TABLE 12-4 Standard Free Energy Change for Phosphate Hydrolysis Compound AGⓇ' (kJ. mol-')...
please help! thanks
TABLE 12-4 Standard Free Energy Change for Phosphate Hydrolysis Compound AGⓇ' (kJ. mol-') Phosphoenolpyruvate -61.9 1,3-Bisphosphoglycerate -49.4 ATP → AMP + PP, -45.6 Phosphocreatine -43.1 ATP ADP + P -30.5 Glucose-1-phosphate -20.9 PP, 2P, -19.2 Glucose-6-phosphate -13.8 Glycerol-3-phosphate -9.2 thioester bond AGⓇ' = -31.5 kJ•mol-1 H20 O CH3 -C-s-CoA I CH3 -C-0- + COA-SH Acetyl-CoA The formation of acetyl CoA from acetate is an ATP driven reaction: Acetate + ATP + COA <--> acetyl COA + AMP...
We have seen all term that cells use the hydrolysis of high energy phosphate from ATP...
We have seen all term that cells use the hydrolysis of high energy phosphate from ATP to make metabolic reactions thermodynamically favorable. Whereas most enzymes that utilize ATP hydrolyze between the b and g phosphates (yielding ADP + Pi), some enzymes hydrolyze ATP between the a and b phosphates (yielding AMP and PPi). ∆G°’ of phosphate hydrolysis is -31 kJ/mol for ATP + H2O --> ADP + Pi, and ∆G°’ of phosphate hydrolysis is -46.5 kJ/mol for ATP + H2O...
5.The following reaction has a ΔG°'--61.9 kJ/mol at 25°C, Phosphoenolpyruvate (PEP) +H2O Pyruvate + Inorganic Phosphate...
5.The following reaction has a ΔG°'--61.9 kJ/mol at 25°C, Phosphoenolpyruvate (PEP) +H2O Pyruvate + Inorganic Phosphate (Pi) (a) Is the reaction favorable under standard biochemical conditions? Explain your answer. (b) What is the equilibrium constant (K) of this reaction at 25°C? In cells the direct hydrolysis of PEP rarely occurs. Rather, the hydrolysis of PEP and the reverse hydrolysis of ATP are coupled (c) w rite out the coupled reaction and determine its ΔG at 25°C The hydrolysis of ATP...
er at initial change (AG The standard free energy change (AG) for ATP hydrolysis is -30.5 kJ/ mol ATP, ADP, and I a...
er at initial change (AG The standard free energy change (AG) for ATP hydrolysis is -30.5 kJ/ mol ATP, ADP, and I are mixed together at initial concentrations of 1 M each then left alone until the reaction below has come to equilibrium. For each species (ie. ATP. ADP and P.) indicate whether the concentration will be equal to 1 M, less than 1 M, or greater than 1 M after the reaction had reached equilibrium. Explain why. ATP +...
Consider the hydrolysis of ATP: ATP(aq) + H2O(l) → ADP(aq) + Pi(aq). This reaction has ΔH°=...
Consider the hydrolysis of ATP: ATP(aq) + H2O(l) → ADP(aq) + Pi(aq). This reaction has ΔH°= −24.3 kJ/mol and ΔS°= +21.6 J/mol-K. The actual concentrations of ATP, ADP, and Pi are not 1 M in a biological cell. How much energy can the conversion of ATP to ADP supply when it occurs at physiological conditions in E. coli where the temperature is 37°C and the approximate concentrations are ATP = 11.2 mM, ADP = 1.52 mM, Pi = 20.0 mM?...
If the aerobic catabolism of 1 mol of glucose yields 38 mol of ATP, and the...
If the aerobic catabolism of 1 mol of glucose yields 38 mol of ATP, and the energy released by aerobic ATP hydrolysis to ADP is –46 kJ/mol, how much energy is available from 1 mol of glucose via aerobic catabolism? (Explain Please)
the delta g for atp synthesis is +34.5 KJ/mol 2. (5 pts) What is the NG...
the
delta g for atp synthesis is +34.5 KJ/mol
2. (5 pts) What is the NG for ATP synthesis (in kJ/mol) in human resting muscle where the concentrations of ATP, ADP, and inorganic phosphate (Pi) are 8 mM, 9M, and 4 mM, respectively and the temperature is 310.15K? Show your work. (30) AG=AGO + RT IN BAT) 4. (5pts) a. Rank the following forms of carbon in order of oxidation state with the most oxidized carbon at the top and...
The last step of glycolysis converts phosphoenolpyruvate to pyruvate. phosphoenolpyruvate + ADP " pyruvate + ATP A G = -33 kJ/mol (-7.5 kcal/mol) The AG" of the reverse reaction is +31 kJ/mol (+7.5 kcal/mol). Instead of reversing the pyruvate kinase reaction, the step is bypassed in gluconeogenesis. Several steps for the conversion of pyruvate to phosphoenolpyruvate via gluconeogenesis are given. Place the steps in the correct order. You will not place all of the steps. First step
The last step of glycolysis converts phosphoenolpyruvate to pyruvate. phosphoenolpyruvate + ADP - pyruvate + ATP A G = -33 kJ/mol (-7.5 kcal/mol) The AG® of the reverse reaction is +31 kJ/mol (+7.5 kcal/mol). Instead of reversing the pyruvate kinase reaction, the step is bypassed in gluconeogenesis. Several steps for the conversion of pyruvate to phosphoenolpyruvate via gluconeogenesis are given. Place the steps in the correct order. You will not place all of the steps. First step Last step Answer...
please help! thanks
TABLE 12-4 Standard Free Energy Change for Phosphate Hydrolysis Compound AGⓇ' (kJ. mol-') Phosphoenolpyruvate -61.9 1,3-Bisphosphoglycerate -49.4 ATP → AMP + PP, -45.6 Phosphocreatine -43.1 ATP ADP + P -30.5 Glucose-1-phosphate -20.9 PP, 2P, -19.2 Glucose-6-phosphate -13.8 Glycerol-3-phosphate -9.2 thioester bond AGⓇ' = -31.5 kJ•mol-1 H20 O CH3 -C-s-CoA I CH3 -C-0- + COA-SH Acetyl-CoA The formation of acetyl CoA from acetate is an ATP driven reaction: Acetate + ATP + COA <--> acetyl COA + AMP...
5.The following reaction has a ΔG°'--61.9 kJ/mol at 25°C, Phosphoenolpyruvate (PEP) +H2O Pyruvate + Inorganic Phosphate (Pi) (a) Is the reaction favorable under standard biochemical conditions? Explain your answer. (b) What is the equilibrium constant (K) of this reaction at 25°C? In cells the direct hydrolysis of PEP rarely occurs. Rather, the hydrolysis of PEP and the reverse hydrolysis of ATP are coupled (c) w rite out the coupled reaction and determine its ΔG at 25°C The hydrolysis of ATP...
er at initial change (AG The standard free energy change (AG) for ATP hydrolysis is -30.5 kJ/ mol ATP, ADP, and I are mixed together at initial concentrations of 1 M each then left alone until the reaction below has come to equilibrium. For each species (ie. ATP. ADP and P.) indicate whether the concentration will be equal to 1 M, less than 1 M, or greater than 1 M after the reaction had reached equilibrium. Explain why. ATP +...
the
delta g for atp synthesis is +34.5 KJ/mol
2. (5 pts) What is the NG for ATP synthesis (in kJ/mol) in human resting muscle where the concentrations of ATP, ADP, and inorganic phosphate (Pi) are 8 mM, 9M, and 4 mM, respectively and the temperature is 310.15K? Show your work. (30) AG=AGO + RT IN BAT) 4. (5pts) a. Rank the following forms of carbon in order of oxidation state with the most oxidized carbon at the top and...
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