Does changes in either concentration or path length result in significant changes in the extinction coefficient....
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Does changes in either concentration or path length result in
significant changes in the extinction coefficient....
Provided that the extinction coefficient for a compound and path length were known, could an absorbance...
Provided that the extinction coefficient for a compound and path length were known, could an absorbance measurement be used to determine concentration? Explain your reasoning.
Assuming a path length of 1-cm and a dsDNA extinction coefficient of 0.020 mL·µg-1·cm-1, what is...
Assuming a path length of 1-cm and a dsDNA extinction coefficient of 0.020 mL·µg-1·cm-1, what is the concentration of dsDNA (in nanograms) if A260 was measured to be 0.041?
A solution contains 0.00750M of a first compound with an extinction coefficient of 22.4cm−1M−1. A second...
A solution contains 0.00750M of
a first compound with an extinction coefficient of 22.4cm−1M−1. A
second compound is added to the solution at a concentration of
0.0260M. The absorbance of the resulting solution is 0.324 with a
path length of 1.00cm. What is the extinction coefficient for the
second compound in the solution? Round the answer to three
significant figures. Give the answer to three significant
figures.
A solution contains 0.00750 M of a first compound with an extinction coefficient...
is there anyway to calculate the absorbance from beer-lambert law? Extinction coefficient = 82 mm-1 concentration...
is there anyway to calculate the absorbance from beer-lambert law? Extinction coefficient = 82 mm-1 concentration = 3.2 mw = 17 dA
QUESTION 8 Calculate the extinction coefficient in (mg/mL) cm from the following data. It is suggested...
QUESTION 8 Calculate the extinction coefficient in (mg/mL) cm from the following data. It is suggested that you use Excel to do this. Give your answer in 3 significant figures. Assume the path length is 1 cm. (You may want to look at the write-up for LAB 19 -1 c (mg/mL) Abs (e 500 nm) 0.001 0.245 0.002 0.490 0.003 0.735 0.004 0.980 0.005 1.100 0.006 1.200 0.007 1.250
100. The following equation: A = 8xlx C (where lis path length and C is concentration)...
100. The following equation: A = 8xlx C (where lis path length and C is concentration) is known as the law. _-Lambert
Which of the following can result in deviations from Beer's law when the path length is...
Which of the following can result in deviations from Beer's law when the path length is constant? Stray light reaching the detector Allradiationnotabsorbedby the sample is transmitted to the detector The use of polychromatic radiation The sample is homogeneous Solute concentrations exceeding 0.01 M
Please answer both 1. Often when handling proteins, we use concentration in terms of mg/ml. A...
Please answer both 1. Often when handling proteins, we use concentration in terms of mg/ml. A high concentration is greater than 1 mg/ml and low concentrations are below 0.1 mg/ml (roughly). If you obtained a sample of MDH that was 10 micromoles/L, what is the concentration in mg/ml? Assume that the molecular weight for MDH is 32 kDa. 2. Using Beer's Law, determine the concentration of your sample if the UV-vis reading at 280 nm was 1.2 absorbance units and...
Use spectroscoplc methods to measure reaction rates Question A solution contains 0.0125 M of some compound. The ab...
Use spectroscoplc methods to measure reaction rates Question A solution contains 0.0125 M of some compound. The absorbance through a path length of 1.00 cm is 0.364. A second compound with an extinction coefficient of 15.2 cmM is added to the solution, and the absorbance through the path length of 1.00 cm increases to 0.455. What is the concentration of the second compound in the solution? Give the answer to three significant figures. Sorry, that's Incorrect. Try again? M
Percent by mass of dye in Fruit Loops cereal 11.56*100 QUESTIONS: 1. If the molar extinction coefficient (E) of a...
Percent by mass of dye in Fruit Loops cereal 11.56*100 QUESTIONS: 1. If the molar extinction coefficient (E) of a compound is 2.5 x 108 moli'cmat $28 nm and the Abs Cat 528 nm) 0.254 Dind the concentration of that solution. (assume a path length of 1.0 cm) 2. If a student measures a sample that gives an Abs = 1.85 at the 2max, is this data reliable? If not, then what might they do to improve their data? 3....
Provided that the extinction coefficient for a compound and path length were known, could an absorbance measurement be used to determine concentration? Explain your reasoning.
A solution contains 0.00750M of
a first compound with an extinction coefficient of 22.4cm−1M−1. A
second compound is added to the solution at a concentration of
0.0260M. The absorbance of the resulting solution is 0.324 with a
path length of 1.00cm. What is the extinction coefficient for the
second compound in the solution? Round the answer to three
significant figures. Give the answer to three significant
figures.
A solution contains 0.00750 M of a first compound with an extinction coefficient...
QUESTION 8 Calculate the extinction coefficient in (mg/mL) cm from the following data. It is suggested that you use Excel to do this. Give your answer in 3 significant figures. Assume the path length is 1 cm. (You may want to look at the write-up for LAB 19 -1 c (mg/mL) Abs (e 500 nm) 0.001 0.245 0.002 0.490 0.003 0.735 0.004 0.980 0.005 1.100 0.006 1.200 0.007 1.250
100. The following equation: A = 8xlx C (where lis path length and C is concentration) is known as the law. _-Lambert
Which of the following can result in deviations from Beer's law when the path length is constant? Stray light reaching the detector Allradiationnotabsorbedby the sample is transmitted to the detector The use of polychromatic radiation The sample is homogeneous Solute concentrations exceeding 0.01 M
Use spectroscoplc methods to measure reaction rates Question A solution contains 0.0125 M of some compound. The absorbance through a path length of 1.00 cm is 0.364. A second compound with an extinction coefficient of 15.2 cmM is added to the solution, and the absorbance through the path length of 1.00 cm increases to 0.455. What is the concentration of the second compound in the solution? Give the answer to three significant figures. Sorry, that's Incorrect. Try again? M
Percent by mass of dye in Fruit Loops cereal 11.56*100 QUESTIONS: 1. If the molar extinction coefficient (E) of a compound is 2.5 x 108 moli'cmat $28 nm and the Abs Cat 528 nm) 0.254 Dind the concentration of that solution. (assume a path length of 1.0 cm) 2. If a student measures a sample that gives an Abs = 1.85 at the 2max, is this data reliable? If not, then what might they do to improve their data? 3....
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