Find the probability value:
P(z <= 1.59)
Find the value of zo, such that:
b.- P(z <=zo) = 0.8508
Find the probability value: P(z <= 1.59) Find the value of zo, such that: b.- P(z...
(1 point) Find the value of the standard normal random variable z, called Zo such that: (a) P(Z <zo) = 0.8319 20 (b) PC-Zo <z<zo) = 0.5508 20 = (c) P(-20 <2<zo) = 0.748 zo = (d) P(z > Zo) = 0.2823 20 = (e) P(-20 <z<0) = 0.0283 Zo = (1) P(-1.5 <2<zo) = 0.7108 zo Note: You can earn partial credit on this problem.
Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfied. a. P(zszo)= 0.0185 b. P(-20 szszo) = 0.95 c. P(-20 szszo) = 0.99 d. P(-20 szszo)=0.8646 e. P(-20 Sz50) = 0.2501 f. P(-2<z<zo)= 0.9612 g. P(z>zo) = 0.5 h. P(z szo)= 0.0076
Find a value of the standard normal random variable z, call it zo such that the following probabilities are satisfied. a. P(z Szo)=0.0473 b. P(- zo szszo)=0.99 c. P(-20 sz szo)=0.95 d. P(-20 52520) = 0 8358 e. P(-20 Sz50)= 0.2612 f. P(-2<z<zo)=0.9503 g. P(z>20)=0.5 h. PZSzo) = 0.0027
1. Find the value of * that yields the probability shown a. P(Z <**)-0.0075 b. P(Z <=*) -0.9850 C. P(Z >z*) - 0.8907 d. P(Z >»*) -0.0110 For #1: a) P(Z < z*) = 0.0075 b) P(Z <z*) = 0.9850 c) P(Z > z*) = 0.8997 d) P(Z > z*) = 0.0110
Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfied a. P(zszo)-0.0483 e. P(-Zo szs0) 0.2945 f.Pl_3czczo)#0.9533 c. P(-20 5zszo)-0.90 d. P(-20 5z5zo)-0.8462 h. P(ZSZo)-0.0049
just number 8 6. 20 = Find zo if (a) Find zb if (b) Find zc if (c) P(-20 < < < zo) = 0.3400 P(Z < zb) = 0.3015 P(Z > ze) = 0.7995 zb = 7. Find x if P(X< x) = 0.6179 X is the normal r.v. N(10,2). x = .. 8. Find y if P(Y<y) = 0.9729, Y is normal r. vN (0,4) y = ........ (a) Find P(x > 110) ifr.v. X = N(100, 102)....
a. Find the value of z subzero such that P(z > zsubzero) = .5 b. Find the value of z subzero such that P(z < zsubzero) = .8643 c. Find the value of z subzero such that P(-z subzero < Z < zsubzero) = .9 d. Find the value of z subzero such that P(-z subzero < Z < zsubzero) = .99
IS Find the following probability for the standard normal random variable z. a. P(z<-1.02) b. P(z <2.03) c. P(0.68 szs2.03) d. P(-2.66szs1.56) a. P(z -1.02)(Round to four decimal places as needed.) b. Pize 2.03)=[] (Round to four decimal places as needed.) ook c. P(0.68 szs2.03) (Round to four decimal places as needed.) d.P(-2.66 s zs 1.56) = [□ (Round to four decimal places as needed.)
For a standard normal probability distribution, find the following a) P(z<1.2) b) P(z<−0.45) c)P(−0.4<z<1.8)
Find a value of the standard normal random variable z, call it 20, such that the following probabilities are satisfied. a. P(zszo)=0.0502 b. P(-2o Szszo)=0.99 c. P(-zo szszo)=0.90 d. P(- zo szszo) = 0.8062 e. P(-Zo Szs 0) = 0.2593 f. P(-3<z<zo)=0.9654 g. Plz>20) = 0.5 h. Plz szo) = 0.0088