write a recursive method to determine if the entire string is uppercase character
import java.util.Scanner; public class IsStringUppercase { public static boolean isUppercase(String s) { if (s.isEmpty()) // base case return true; return !(s.charAt(0) >= 'a' && s.charAt(0) <= 'z') && isUppercase(s.substring(1)); // recursive case } public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.print("Enter a string: "); String str = in.nextLine(); if (isUppercase(str)) { System.out.println(str + " is in uppercase"); } else { System.out.println(str + " is not in uppercase"); } } }
write a recursive method to determine if the entire string is uppercase character
Java Program Write a recursive method that takes a string and return a string where every character appears twice. Output must match exactly as below: only two LL's since there is already two of the character For example, if the string is “HELLO”, it will return “HHEELLOO”. Write a program to test it. must be recursive!!!
java 2. Write a recursive method to return the number of occurrences a character c in a string s. c and s should be parameters.
Write a recursive method that counts the number of vowels in a string. It must return the number of vowels. Use appropriate parameters as needed. Hint: There's an ArrayList method called contains that might make checking whether a character is a vowel easier.
Write a recursive function to convert a character string of digits to an integer. Example: convert(“1234”) returns 1234. Hint: To convert a character to a number, subtract the ASCII value ‘0’ from the character. For example, if the string s has only one character, then the function can return the value s[0] – ‘0’.
//Write a recursive function that, given an input string str, replaces all occurrences of a character a by a character b in str. (C++) void replace_chr(char *str, char a, char b){ }
2) Write a function stringManip that takes in a character string and returns a character string following these rules: a) any vowel (a, e, i, o, u) is replaced by the character '&' b) any numeric character has 1 added to it (if it was 9, it becomes O instead) (str2num() is useful here) c) all lowercase characters become uppercase d) replace the final character with '!' e) append the length of the string before this step to the end...
Your assignment is to write an assembly language program which read a string and print it in uppercase. This program asks the user to enter a string which is subsequently displayed in uppercase. It is important to first ensure that string to be converted is in the a-z range. The program does not recognize any space, symbols or any kind of punctuation marks. Any time the user enters any of this character the program is going to repeatedly ask for...
1.) Write a recursive function named isPalindrome that will take a single string as an argument and determine if the argument is a palindrome. The function must return True if the argument is a palindrome, False otherwise. Recall that any string is a palindrome if its first and last characters are the same and the rest of it is also a palindrome (therefore, a single character is a palindrome): 2.) Consider a text file named samplestrings.txt that contains a collection...
[10 marks] Write a recursive method, reverse, that displays a string in a reverse order. For example, reverse("UBC-O") displays O-CBU. Use a helper method to improve the performance of your program. Write a test program that prompts the user to enter a string and displays its reversal. MUST HAVE A HELPER METHOD TO IMPROVE PERFORMANCE. FOR JAVA THANK YOU!
Write a program that uses a recursive function to determine whether a string is a character-unit palindrome. Moreover, the options for doing case sensitive comparisons and not ignoring spaces are indicated with flags. For example "A nut for a jar of tuna" is a palindrome if spaces are ignored and not otherwise. "Step on no pets" is a palindrome whether spaces are ignored or not, but is not a palindrome if it is case sensitive. Background Palindromes are character sequences...