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The decomposition of crystalline N2O5 N2O5 (s) —> 2 NO2 (g) + 1/2 O2 (g) is...

The decomposition of crystalline N2O5
N2O5 (s) —> 2 NO2 (g) + 1/2 O2 (g)
is an example of a reaction that is thermodynamically favored even though it absorbs heat. At 25°C we have the following values for the standard state entrapped and free energy changes of the reaction:
ΔH° = +109.6 kJ/mol
ΔG° = -30.5 kJ/mol
a. Calculate ΔS° at 25°C
b. Why is the entropy change so favorable for this reaction?

Please answer and explain both questions!
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Answer #1

entropy change is so favourable because there great change in number of moles in product in compare to reactant as number of mole of product is increase as compare to mole of reactant. And increase number of mole is favourable for entropy change.

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