entropy change is so favourable because there great change in number of moles in product in compare to reactant as number of mole of product is increase as compare to mole of reactant. And increase number of mole is favourable for entropy change.
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The decomposition of crystalline N2O5 N2O5 (s) —> 2 NO2 (g) + 1/2 O2 (g) is...
The decomposition of crystalline N2O5 N2O5(s)⟶2NO2(g)+12O(g) is an example of a reaction that is thermodynamically favored even though it absorbs heat. At 25 ∘C we have the following values for the standard state enthalpy and free energy changes of the reaction: ΔH∘=+109.6kJ/mol ΔG∘=−30.5kJ/mol c. What is driving the reaction forwards: enthalpy, entropy or both?
Need the answer to part B The decomposition of crystalline N, O N,Og(s) + 2NO2(g) + 0(g) is an example of a reaction that is thermodynamically favored even though it absorbs heat. At 25°C we have the following values for the standard state enthalpy and free energy changes of the reaction: AH = +109.6 kJ/mol AG° = -30.5 kJ/mol Part A Calculate AS at 25°C. Express your answer with the appropriate units. AS° = 470 melk Submit Previous Answers All...
The decomposition of N2O5 proceeds according to the following equation: 2 N2O5 (g) -> 4 NO2 (g) + O2 (g) If the rate of decomposition of N2O5 at a particular instant in a reaction vessel is 5.3 x 10-5 M/s, what is the rate of appearance of NO2?
3. The rate of decomposition of N2O5 in the reaction 2 N2O5(g) 4 NO2(g) + 5 O2(g) at a particular instant is 4.2 x 10-7 M/s, what is the rate of appearance of NO2?
Consider the rate of decomposition: 2 N2O5(g) → 4NO2(g) + O2(g). The rate of reaction will be dependent on: A. [N2O5] B. [NO2] C. [O2] D. [NO2] and [O2]
Ozone (O3) in the atmosphere can react with nitric oxide (NO): O3(g) + NO(g) --> NO2(g) + O2(g). ( ΔH° = –199 kJ/mol, ΔS° = –4.1 J/K·mol) Write answers to three significant figures. a. Calculate the ΔG°( kJ/mol) for this reaction at 25°C. b. Determine the temperature(oC) at which the reaction is at equilibrium.
Ozone (O3) in the atmosphere can react with nitric oxide (NO): O3(g) + NO(g) --> NO2(g) + O2(g). ( ΔH° = –199 kJ/mol, ΔS° = –4.1 J/K·mol) Write answers to three significant figures. a. Calculate the ΔG°( kJ/mol) for this reaction at 25°C. Blank 1 b. Determine the temperature(oC) at which the reaction is at equilibrium.
(6) (1 point) Using the data below, NO(g) + NO2(g) + N203(9) NO(g) + NO2(g) + O2(g) → N205(9) 2 NO2(g) + N20 (9) 2 NO(g) + O2(g) → 2 NO2(g) N205(9) + N2O5(s) AH° = -39.8 kJ AH° = -112.5 kJ AH° = -57.2 kJ AH° = -114.2 kJ AH° = -54.1 kJ compute the heat of reaction for, N2039) + N2O5(s) + 2 N204(9). (6) (1 point) Using the data below, NO(g) + NO2(g) + N203(9) NO(g) +...
The gas phase reaction 2 N2O5(g) → 4 NO2(g) + O2(g) has an activation energy of 103 kJ/mol, and the first order rate constant is 1.01×10-4 min-1 at 278 K. What is the rate constant at 308 K? ________min-1
Consider the following data. 2 H2(g) + O2(g) 2 H2O(l) ΔH = -571.7 kJ N2O5(g) + H2O(l) 2 HNO3(l) ΔH = -92.0 kJ N2(g) + 3 O2(g) + H2(g) 2 HNO3O(l) ΔH = -348.2 kJ Use Hess's law to calculate ΔH for the reaction below. 2 N2O5(g) 2 N2(g) + 5 O2(g) ΔH = _____kJ