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The decomposition of crystalline N2O5 N2O5(s)⟶2NO2(g)+12O(g) is an example of a reaction that is thermodynamically favored...

The decomposition of crystalline N2O5 N2O5(s)⟶2NO2(g)+12O(g) is an example of a reaction that is thermodynamically favored even though it absorbs heat. At 25 ∘C we have the following values for the standard state enthalpy and free energy changes of the reaction: ΔH∘=+109.6kJ/mol ΔG∘=−30.5kJ/mol c. What is driving the reaction forwards: enthalpy, entropy or both?

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It is both the enthalpy and entropy of the reaction which drives the reaction in forward direction as if we substitute the values in formaula delta G= detla H -T delta S , we get Delta S= 470KJ/ K/mol and delta H = 109.6 KJ/ mol. Since both are positive so the reaction is in forward direction .

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