Suppose X ∼ N (100, 5 2 ). Find P(95 ≤ X ≤ 110). Geometrically sketch what this probability represents.
Suppose X ∼ N (100, 5 2 ). Find P(95 ≤ X ≤ 110). Geometrically sketch...
8. Suppose XN(100,52). Find P(95 < X < 110). 9. Suppose X is a normal random variables with parameters x = 10 and o2 = 36. Compute (a) P(X > 5) and geometrically sketch what you have found. (b) P(4 < X < 16) and geometrically sketch what you have found. (c) P(X < 8) and geometrically sketch what you have found.
5)Suppose that X ∼ U(-5, 10). Find the P(-2 ≤ X ≤ 5) Round your answer to the nearest thousandth. 6) Suppose that X ∼ N(-1.5,2.6), Y ∼ N(2.7,1.4), and Z ∼ N(1.4, 0.9) are independent random variables. Find the probability that |2.4X + 3Y + 4Z| ≥ 10.7. Round your answer to the nearest thousandth.
1) Suppose that X ∼ N(0,1) find: P(X<=1.36) Round your answer to the nearest thousandth. 2) Suppose that X ∼ N(0,1) find: P(|X-0.9|>=1.35) Round your answer to the nearest thousandth. 3)Suppose that X ∼ B(8, 0.25). Calculate p(X=1) Round your answer to the nearest thousandth. 4) Suppose that X ∼ B(10, 0.23). Calculate P(X ≥ 7) Round your answer to the nearest thousandth. 5)Suppose that X ∼ U(-5, 10). Find the P(-2 ≤ X ≤ 5) Round your answer to...
n 110. If n, p, and x are positive integers, and 2. +2, P. then P n 1 E. x + 2 2 x + 2 F. G. х 2x+2 1 H. + 2
Statics: Math 122 n-100 4) Finda 95% confidence interval for p, given p-046(n 100). 5 digits a) Use the formula directly: ( b) Use your TI-84 technology: ( 5) That does your binomialcdf technology say regarding your answers to the problem #4 above? (Hint: x-pn)
Problem 41.3 Let X and Y be independent random variables each geometrically distributed with parameter p, i.e. p(1- p otherwise. Find the probability mass function of X +Y
2. Let X be a binomial variable with n=10. Suppose E(X) - 3. (a) (5 points) What is the probability of success of the binomial experiment that generates the variable X? Explain your answer. (b) (5 points) Find P(X = 3). (c) (5 points) Find P(3 < X < 7). (d) (5 points) Find P(X 1 )
Yes No Girls 42 ,110 Boys 95, 53 a. If b represents the event of selecting a response from a boy, find the complement of b [P(Ђ)]. 148/300=0.493 1-0.493=0.507 ? b. Find the probability that the selected answer was no [P(no)]. ? c. If g represents the event of selecting a response from a girl, find the complement of g [P (ḡ)]. 0.493? d. Find the probability that the selected answer was yes [P(yes)].?
(30 points) Suppose x-N(30,144), and W-N(40,225). 4a. If X and W are uncorrelated, find the mean and variance of X 2W 4b. Find the probability that X + 2W > 100. Henceforth, suppose that X and W have a correlation coefficient p25 4c. What is the covariance of X and W? 4d. Find the probability that X 2W > 100. 4e. Find the probability that 50 < X 2W 120
6. Let X N (100, 25). Find the following: (a) P(X < 100) Answer: 1/2, (b) P(X> 100) Answer: 1/2, (c) P(X 100) Answer: 0, (d) the 99th percentile for this distribution Answer: approx 111.632. (5.4.2)