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25.00 mL of 1M NaOH was diluted with 75.78 mL of water. This was used in...

25.00 mL of 1M NaOH was diluted with 75.78 mL of water. This was used in a titration of 0.984 mg of an unknown acid, and it took 28.45 mL of diluted NaOH to bring this solution to the equivalence point.

What is the unkown solid acids molar mass (grams/mole)?

What is it's pKa?

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