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For the 2.50 mole sample of the gas with the equation of state given The gas...

For the 2.50 mole sample of the gas with the equation of state given The gas is described by the equation of state PV=n(RT+PB)where B = 82.0 cm3/mole. expand the gas from 20.0 bar to 2.00 bar isothermally at 500 K, and calculateΔA and ΔG.

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Answer #1

We know that the formulae to calculate ΔA and ΔG are:

Since,
ΔE and ΔH both are functions of temperature, therefore ΔE = ΔH = 0

Therefore, ΔA = ΔG = -TΔS.

Now, we know that according to the 2nd law of thermodynamics:

And according to the first law of thermodynamics, for an isothermal process:

So, ΔG = ΔA = -28101.97J

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