A particle of mass 2 kg is moving in the xy plane at a constant speed of 0.80 m/s in the +x direction along the line y=4m. As the particle travels from ,x= -3m to x= +3m, the magnitude of its angular momentum with respect to the origin is
A] not constant
B] 0
C} 4.8 kg m2/s
D} 8.4 kg m2/s
E} 8 kg m2/s
Solution :
Since the Angular momentum is given by :
L = m v r
Here,
m = 2 kg
v = 0.80 m/s
r = 4 m
Thus : L = (2 kg)(0.80 m/s)(4 m) = 6.4 kg m2 / s
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