Question

Consider the following balanced equation: 16HCl(aq) + 2KMnO4(aq) → 5Cl2(g) + 8H2O(l) + 2KCl(s) + 2MnCl2(aq)...

Consider the following balanced equation: 16HCl(aq) + 2KMnO4(aq) → 5Cl2(g) + 8H2O(l) + 2KCl(s) + 2MnCl2(aq)

If 8.53×102 grams of HCl(aq) reacts with an excess of KMnO4(aq), and the percent yield is 72.6%, how many grams of KCl(s) will actually be produced?

9.13×102 g

1.58×102 g

8.82×102 g

4.38×102 g

9.33×102 g

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Consider the following balanced equation: 16HCl(aq) + 2KMnO4(aq) → 5Cl2(g) + 8H2O(l) + 2KCl(s) + 2MnCl2(aq)...
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