Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) If 15.8 moles of Ca(...
Consider the following balanced equation:
3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq)
If 15.8 moles of Ca(ClO3)2(aq) reacts with an excess of Li3PO4(aq), and the percent yield is 63.3%, how many moles of LiClO3(aq) will actually be produced
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Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) If 15.8 moles of Ca(...
Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) If 41.0 moles of...
Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) If 41.0 moles of Li3PO4(aq) reacts with an excess of Ca(ClO3)2(aq) to produce 61.9 moles of LiClO3(aq), what is the percent yield of the reaction?
Consider the balanced equation for the following reaction: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) How...
Consider the balanced equation for the following reaction: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) How much excess reactant remains in the reaction if 44.1 grams of Ca(ClO3)2 reacts with 55.3 grams of Li3PO4?
Consider the following unbalanced equation: Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq) If 38.3 moles of...
Consider the following unbalanced equation: Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq) If 38.3 moles of Li3PO4(aq) reacts with an excess of Ca(ClO3)2(aq), what is the theoretical yield of LiClO3(aq) in moles?
Consider the following unbalanced equation: Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq...
Consider the following unbalanced equation: Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq) If 63.2 moles of Ca(ClO3)2(aq) and 22.3 moles of Li3PO4(aq) are allowed to react to produce 40.4 moles of LiClO3(aq), what is the percent yield of the reaction?\ 47.5% 63.8% 73.1% 60.4% 84.0%
Consider the balanced equation for the following reaction: 2H3PO4(aq) + 3Ca(OH)2(s) → 6H2O(l) + Ca3(PO4)2(s) How much ex...
Consider the balanced equation for the following reaction: 2H3PO4(aq) + 3Ca(OH)2(s) → 6H2O(l) + Ca3(PO4)2(s) How much excess reactant remains in the reaction if 7.83 moles of H3PO4 reacts with 1.53 moles of Ca(OH)2? 7.83 moles 2.61 moles 0.510 moles 6.30 moles 6.81 moles
Consider the following unbalanced equation: H3PO4(aq) + Ca(OH)2(s) → H2O(l) + Ca3(PO4)2(s) If 34.1 moles of...
Consider the following unbalanced equation: H3PO4(aq) + Ca(OH)2(s) → H2O(l) + Ca3(PO4)2(s) If 34.1 moles of H3PO4(aq) reacts with an excess of Ca(OH)2(s), what is the theoretical yield of H2O(l) in moles? O 6.34x102 moles 6.42x102 moles 1.02x102 moles 8.34x102 moles 8.37x102 moles 0 O
Consider the net ionic equation: 3Ca+2 (aq) + 2PO4-3 (aq) → Ca3(PO4)2 (s) Which of the...
Consider the net ionic equation: 3Ca+2 (aq) + 2PO4-3 (aq) → Ca3(PO4)2 (s) Which of the following unbalanced chemical equations could give rise to this net ionic equation? A. CaCl2 + Na3PO4 → Ca3(PO4)2 + H2O B. CaC2 + H3PO4 → Ca3(PO4)2 + C2H2 C. Both of the above reactions. D. None of the above reactions
Na3PO4(aq) + Ca(NO3)2(aq) → NaNO3(aq) + Ca3(PO4)2(s) Determine the amount of NaNO3(aq) formed in the reaction...
Na3PO4(aq) + Ca(NO3)2(aq) → NaNO3(aq) + Ca3(PO4)2(s) Determine the amount of NaNO3(aq) formed in the reaction if 3.30 moles of Ca(NO3)2(aq) reacts with an excess of Na3PO4(aq) and the percent yield of NaNO3(aq) is 71.0%. A. 6.24 moles B. 9.30 moles C. 4.69 moles D. 7.50 moles E. 8.96 moles
6)# What is the limiting reactant for the following reaction given we have 3.4 moles of...
6)# What is the limiting reactant for the following reaction given we have 3.4 moles of Ca(NO3)2 and 2.4 moles of Li3PO4? Reaction: 3Ca(NO3)2 + 2Li3PO4 ---> 6LiNO3 + Ca3(PO4)2 Answer (show work please?) Ca3(PO4)2 Li3PO4 Ca(NO3)2 LiNO3 not enough information
How many grams of Ca3(PO4)2 precipitate can form by reacting 258.6 mL of 1.8 M CaBr2...
How many grams of Ca3(PO4)2 precipitate can form by reacting 258.6 mL of 1.8 M CaBr2 with an excess amount of Li3PO4, given the balanced equation: 2 Li3PO4 (aq) + 3 CaBr2 (aq) --> 6 LiBr2 (aq) + Ca3(PO4)2 (s)
Consider the following unbalanced equation: H3PO4(aq) + Ca(OH)2(s) → H2O(l) + Ca3(PO4)2(s) If 34.1 moles of H3PO4(aq) reacts with an excess of Ca(OH)2(s), what is the theoretical yield of H2O(l) in moles? O 6.34x102 moles 6.42x102 moles 1.02x102 moles 8.34x102 moles 8.37x102 moles 0 O
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