6)# What is the limiting reactant for the following reaction given we have 3.4 moles of...
6)#
What is the limiting reactant for the following reaction given we
have 3.4 moles of Ca(NO3)2 and 2.4 moles of Li3PO4?
Reaction: 3Ca(NO3)2 + 2Li3PO4 ---> 6LiNO3 + Ca3(PO4)2
Answer (show work please?)
Ca3(PO4)2
Li3PO4
Ca(NO3)2
LiNO3
not enough information
Homework Answers
: 3Ca(NO3)2 + 2Li3PO4 ---> 6LiNO3 + Ca3(PO4)2
according to balanced reaction
3 moles Ca(NO3)2 reacts with 2 moles Li3PO4
3.4 moles Ca(NO3)2 reacts with 3.4 x 2 / 3 = 2.3 moles Li3PO4
but we have 2.4 moles of Li3PO4 . means exess Li3PO4 present
so exess reagent = Li3PO4
limiting reagent = Ca(NO3)2
answer = Ca(NO3)2
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6)#
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