Consider the balanced equation for the following reaction: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) How...

Question

Question

Consider the balanced equation for the following reaction:

3Ca(ClO₃)₂(aq) + 2Li₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6LiClO₃(aq)

How much excess reactant remains in the reaction if 44.1 grams of Ca(ClO₃)₂ reacts with 55.3 grams of Li₃PO₄?

Answer 1

Answer #1

3ca (C103)2+2 42PO4 → Cq3(PO4)276Licos Now, moles of cacC103%= mass . molar mass = 44.1 g -0.913 mol २०२ १०१०) moles of liz p

Answer 2

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