Consider the following unbalanced equation:
Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq)
If 63.2 moles of Ca(ClO3)2(aq) and 22.3 moles of Li3PO4(aq) are allowed to react to produce 40.4 moles of LiClO3(aq), what is the percent yield of the reaction?\
47.5%
63.8%
73.1%
60.4%
84.0%
Consider the following unbalanced equation: Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq...
Consider the following unbalanced equation: Ca(ClO3)2(aq) + Li3PO4(aq) → Ca3(PO4)2(s) + LiClO3(aq) If 38.3 moles of Li3PO4(aq) reacts with an excess of Ca(ClO3)2(aq), what is the theoretical yield of LiClO3(aq) in moles?
Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) If 41.0 moles of Li3PO4(aq) reacts with an excess of Ca(ClO3)2(aq) to produce 61.9 moles of LiClO3(aq), what is the percent yield of the reaction?
Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) If 15.8 moles of Ca(ClO3)2(aq) reacts with an excess of Li3PO4(aq), and the percent yield is 63.3%, how many moles of LiClO3(aq) will actually be produced
Consider the balanced equation for the following reaction: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq) How much excess reactant remains in the reaction if 44.1 grams of Ca(ClO3)2 reacts with 55.3 grams of Li3PO4?
Consider the following unbalanced equation: H3PO4(aq) + Ca(OH)2(s) → H2O(l) + Ca3(PO4)2(s) If 34.1 moles of H3PO4(aq) reacts with an excess of Ca(OH)2(s), what is the theoretical yield of H2O(l) in moles? O 6.34x102 moles 6.42x102 moles 1.02x102 moles 8.34x102 moles 8.37x102 moles 0 O
Na3PO4(aq) + Ca(NO3)2(aq) → NaNO3(aq) + Ca3(PO4)2(s) Determine the amount of NaNO3(aq) formed in the reaction if 3.30 moles of Ca(NO3)2(aq) reacts with an excess of Na3PO4(aq) and the percent yield of NaNO3(aq) is 71.0%. A. 6.24 moles B. 9.30 moles C. 4.69 moles D. 7.50 moles E. 8.96 moles
Consider the net ionic equation: 3Ca+2 (aq) + 2PO4-3 (aq) → Ca3(PO4)2 (s) Which of the following unbalanced chemical equations could give rise to this net ionic equation? A. CaCl2 + Na3PO4 → Ca3(PO4)2 + H2O B. CaC2 + H3PO4 → Ca3(PO4)2 + C2H2 C. Both of the above reactions. D. None of the above reactions
Consider the balanced equation for the following reaction: 2H3PO4(aq) + 3Ca(OH)2(s) → 6H2O(l) + Ca3(PO4)2(s) How much excess reactant remains in the reaction if 7.83 moles of H3PO4 reacts with 1.53 moles of Ca(OH)2? 7.83 moles 2.61 moles 0.510 moles 6.30 moles 6.81 moles
What is the concentration of calcium ion that results from the unbalanced reaction Ca3(PO4)2(s)= Ca2+ (aq) +P04(ag) Where K=1.77x10-4
c. (10 pts.) Using the equation: 3 S-Cl2 (aq) + 2 Li3PO4 (aq) → Sr3(PO4)2 (8) + 6 LICI (aq) If you are given 5.80 g of SrCl2 and 2.45 g of Li3PO4, which of the two compounds is the limiting reactant, and what is the theoretical yield (in grams)? src S 8762)*1 is 4.524