Suppose a small light source is placed at the center of two transparent spheres. One sphere...
Suppose a small light source is placed at the center of two transparent spheres. One sphere has a radius R, and the other a radius 2R. Energy in the form of light leaves the source at a rate P. Intensity (I) is the energy (P) per unit area (A).
According to conservation of energy, how does the total energy passing through the inner sphere compare to the total energy reaching the outer sphere?
1.What is the formula for the surface area of a sphere?
2.How do the surface areas of the two spheres compare (be specific)?
3.How does the intensity of the two spheres compare (be specific)?
4.In general, what is the formula for intensity in terms of the power and radius
Homework Answers
1) A = 4
r2
where r is the radius of the sphere
2) Surface area of outer sphere is greater.
surface area of inner sphere = 4R2
surface area of outer sphere = 16R2
3) Intensity = power / area
so, if area is more, intensity will be less.
intensity of light will be more for smaller sphere.
Also, Intensity will decrease exponentially as the distance from the source increases
4) Intensity = power / area
Intensity = p / 4r2
Therefore, we can say that Energy passing through the inner sphere is 4 times the energy passing through the outer sphere.
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