Given the following information, construct a Born-Haber cycle to
calculate the lattice energy of CaC2(s):
Net energy change for the formation of CaC2(s)=−60kJ/mol
Heat of sublimation for Ca(s)=+178kJ/mol
Ei1 for Ca(g)=+590kJ/mol
Ei2 for Ca(g)=+1145kJ/mol
Heat of sublimation for C(s)=+717kJ/mol
Bond dissociation energy for C2(g)=+614kJ/mol
Eea1 for C2(g)=−315kJ/mol
Eea2 for C2(g)=+410kJ/mol
Express your answer using four sig figs
Given the following information, construct a Born-Haber cycle to calculate the lattice energy of CaC2(s): Net...
Construct a Born-Haber cycle and calculate the lattice energy of CaC2 (s). Note that this solid contains the diatomic ion C22–.Useful Information:?H°f (CaC2(s)) ?Hsub (Ca (s)) ?Hsub (C (s)) Bond dissociation energy of C2 (g) = +614 kJ/molFirst ionization energy of Ca (g) = +590 kJ/mol Second ionization energy of Ca (g) = +1143 kJ/mol First electron affinity of C2 (g) = –315 kJ/mol Second electronaffinity of C2 (g) = +410 kJ/mol= –60 kJ/mol = +178 kJ/mol = +717 kJ/mol
7. Use the Born Haber cycle and the given information to determine the net energy change (in kJ/mol) that takes place in the formation of KF(s) from the elements: Ks) + F2@KFS) Heat of sublimation of K = 89.2 kJ/mol Bond dissociation energy for F2 = 158 kJ/mol Lattice Energy of KF = 821 kJ/mol Eca for F = -328 kJ/mol E; for K = 418.8 kJ/mol
4) Calculate the lattice enthalpy for calcium fluoride using the Born-Haber cycle method, using the provided table. (Show all your work; 2 points) Enthalpies, AH/(kJ mol) +192 Process Sublimation of Ca(s) Ionization of Ca(g) Dissociation of F2(g) Electron gain by F(g) Formation of CaF (s) +1735 to Ca(ag +157 -328 -1220
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
Draw the Born-Haber Cycle with these values and calculate lattice energy. Problem 1: Label each reaction listed below for the Born-Haber cycle in the formation of Cao lattice and calculate the lattice energy of Cal given the following information. AH KD) Ca(s) + Ca(8) 193 Calg) - Cat (8) + e 590 Cat (8) - Cat (8) + e- 2 O(g) + O2(g) O(8) + e- O (8) -141 O (8) + e- O (8) 878 Ca(s) + O2(g) →...
Calculate the net energy change in kilojoules per mole that takes place on formation of BeF2(s) from the elements: Be(s)+F2(g)⟶BeF2(s) The following information is needed: Heat of sublimation for Be(s)= 325.8 kJ/mol Eea for F(g)= −328 kJ/mol Bond dissociation energy for F2(g)= 158 kJ/mol Ei1 for Be(g)= 899.5 kJ/mol Electrostatic interactions in BeF2(s)= −3505 kJ/mol Ei2 for Be(g)= 1757.1 kJ/mol
Using the data given below, sketch a Born-Haber cycle for the formation of BaC2(s) and insert the various equations and energy values into the individual steps of your cycle Sublimation energy for Ba(s) +180 kJmol1 Electron affinity for Cl(g)-346 kJmol1 First ionization energy for Ba(g)-+514 kJmol1 Bond dissociation energy for Clh(g) +243 kJmol Enthalpy of formation of BaCl2: Ba(s) + Ch(g) BaCh(s)--610 kJmol Lattice energy. Ba2+(g) + 2Cl.(g) → BaCl2(s)--2075 kJmol-1 Calculate the second ionization energy for Ba+(g) → Ba2+(g)...
Calculate the energy change (in kilojoules per mole) for the formation of the following substances from their elements. CaF2 (The sublimation energy for Ca is +178.2 kJ/mol, Ei1 = +589.8 kJ/mol, Ei2 = +1145kJ/mol, and the lattice energy of CaF2 is 2630 kJ/mol.) Express the energy change in kilojoules per mole to four significant digits.
Using the thermodynamic quantities shown below: construct a Born-Haber cycle for the following reaction: Li(s) + 1/2 F2(g) LiF(s); calculate the lattice energy of LiF. Vaporization of Li(s): +159 F2 bond enthalpy: +155 Li ionization energy: +520 F- electron affinity: +328 LiF(s) heat of formation: -616
Calculate the net change in energy in kJ that takes place on formation of 50.44 moles of MgF2(s) from Mg(s) + F2(g) → MgF2(s) given the following information: Heat of sublimation for Mg(s) = 147.7 kJ/mol Bond dissociation energy for F2(g) = 158 kJ/mol Electrostatic interactions in MgF2(s) = -2957 kJ/mol Eea for F(g) = -328 kJ/mol Ei1 for Mg(g) = 737.7 kJ/mol Ei2 for Mg(g) = 1450.7 kJ/mol