7. Use the Born Haber cycle and the given information to determine the net energy change...
Calculate the net energy change in kilojoules per mole for the formation of KF(s) from the elements: K(s) + 1/2 F2(g) \rightarrow→KF(s). The following information is given: Heat of sublimation for K(s) = 89.2 kJ/mol, Eea for F(g) = –328 kJ/mol Bond dissociation energy for F2(g) = 158 kJ/mol, Ei for K(g) = 418.8 kJ/mol Electrostatic interactions in KF(s) = –821 kJ/mol
Given the following information, construct a Born-Haber cycle to calculate the lattice energy of CaC2(s): Net energy change for the formation of CaC2(s)=−60kJ/mol Heat of sublimation for Ca(s)=+178kJ/mol Ei1 for Ca(g)=+590kJ/mol Ei2 for Ca(g)=+1145kJ/mol Heat of sublimation for C(s)=+717kJ/mol Bond dissociation energy for C2(g)=+614kJ/mol Eea1 for C2(g)=−315kJ/mol Eea2 for C2(g)=+410kJ/mol Express your answer using four sig figs
4) Calculate the lattice enthalpy for calcium fluoride using the Born-Haber cycle method, using the provided table. (Show all your work; 2 points) Enthalpies, AH/(kJ mol) +192 Process Sublimation of Ca(s) Ionization of Ca(g) Dissociation of F2(g) Electron gain by F(g) Formation of CaF (s) +1735 to Ca(ag +157 -328 -1220
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
Calculate the net energy change in kilojoules per mole that takes place on formation of BeF2(s) from the elements: Be(s)+F2(g)⟶BeF2(s) The following information is needed: Heat of sublimation for Be(s)= 325.8 kJ/mol Eea for F(g)= −328 kJ/mol Bond dissociation energy for F2(g)= 158 kJ/mol Ei1 for Be(g)= 899.5 kJ/mol Electrostatic interactions in BeF2(s)= −3505 kJ/mol Ei2 for Be(g)= 1757.1 kJ/mol
Calculate the net change in energy in kJ that takes place on formation of 50.44 moles of MgF2(s) from Mg(s) + F2(g) → MgF2(s) given the following information: Heat of sublimation for Mg(s) = 147.7 kJ/mol Bond dissociation energy for F2(g) = 158 kJ/mol Electrostatic interactions in MgF2(s) = -2957 kJ/mol Eea for F(g) = -328 kJ/mol Ei1 for Mg(g) = 737.7 kJ/mol Ei2 for Mg(g) = 1450.7 kJ/mol
Calculate the enthalpies of formation, ΔHfo, of the following group 1 fluoride compounds from their elements using the Born–Haber cycle. NaF RbF Number Number kJ ol kJ mol AHO, kJ/mol Sublimation of Na(s) 108 86 Sublimation of Rb(s) 158 Dissociation of F2(g Ionization energy of Na(g) 496 ionization energy of Rb(g) 403 Electron affinity of F(g) -322 Lattice enthalpy of NaF(s) 926 Lattice enthalpy of RbF(s) 789
Using the thermodynamic quantities shown below: construct a Born-Haber cycle for the following reaction: Li(s) + 1/2 F2(g) LiF(s); calculate the lattice energy of LiF. Vaporization of Li(s): +159 F2 bond enthalpy: +155 Li ionization energy: +520 F- electron affinity: +328 LiF(s) heat of formation: -616
OADVANCED MATERIAL Interpreting a Born-Haber cycle This thermodynamic cycle describes the formation of an ionic compound M X2 from a metal element M and nonmetal element X in their standard states. Use it to answer the questions in the table below. 2+ 1100 1000 900 2- 800--- 700 600 M (8)+2X) 500. enthalpy 400 (kJ/mol) 300. M (g) + X, (g) 200 ▼ | 700,- 600 M (g) + 2x (g 500 enthalpy 400. 300. м (е) + x, (g)...
Use the Born-Haber Cycle and information given below to determine the lattice energy of LiF. Li(s) → Li(g) +159.3 kJ Li(g) → Li+(g) + e– +500.9 kJ F2(g) → 2 F(g) +158.8 kJ F(g) + e– → F–(g) –332.6 kJ Li+(g) + F–(g) → LiF(s) ? --------------------------------------------------- Li(s) + ½ F2(g) → LiF(s) – 616.0 kJ Group of answer choices +209.0 kJ –1023 kJ +1023 kJ –209.0 kJ –1102.4 kJ