4) Calculate the lattice enthalpy for calcium fluoride using the Born-Haber cycle method, using the provided...
Calculate the enthalpies of formation, ΔHfo, of the following group 1 fluoride compounds from their elements using the Born–Haber cycle. NaF RbF Number Number kJ ol kJ mol AHO, kJ/mol Sublimation of Na(s) 108 86 Sublimation of Rb(s) 158 Dissociation of F2(g Ionization energy of Na(g) 496 ionization energy of Rb(g) 403 Electron affinity of F(g) -322 Lattice enthalpy of NaF(s) 926 Lattice enthalpy of RbF(s) 789
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
Using the thermodynamic quantities shown below: construct a Born-Haber cycle for the following reaction: Li(s) + 1/2 F2(g) LiF(s); calculate the lattice energy of LiF. Vaporization of Li(s): +159 F2 bond enthalpy: +155 Li ionization energy: +520 F- electron affinity: +328 LiF(s) heat of formation: -616
Given the following information, construct a Born-Haber cycle to calculate the lattice energy of CaC2(s): Net energy change for the formation of CaC2(s)=−60kJ/mol Heat of sublimation for Ca(s)=+178kJ/mol Ei1 for Ca(g)=+590kJ/mol Ei2 for Ca(g)=+1145kJ/mol Heat of sublimation for C(s)=+717kJ/mol Bond dissociation energy for C2(g)=+614kJ/mol Eea1 for C2(g)=−315kJ/mol Eea2 for C2(g)=+410kJ/mol Express your answer using four sig figs
Knowing the enthalpy of formation of calcium fluoride is -1228 KJ / mol, the enthalpy of the sublimation of calcium is 168kj/mole, the bond enthalpy of fluorine is 155kj/mole, the electron affinity of fluorine is -328 kj/mole, the first ionization enthalpy of calcium is 590kj/mole and the second ionization enthaply is 1145kj/mole, calculate the lattice enthalpy of calcium fluoride.
Structure with an (8,4) coordination unit cell (0) Given the b. Calcium fluorite (CaF2) has a fluorite structure with an (8,4) coordina Given the following data, use Born-Haber cycle to calculate the lattice enthalpy of CaF2 AH KJ/mol +178 +1228 Sublimation of Ca(s) Decomposition of CaF2(s) Dissociation of F2(g) lonisation of Ca(s) lonisation of Ca (8) Electron gain of F(b) +79 +590 +1145 -328 Given the following data d* = 0.345x10-11m, K=1.20 MJÅ. mol-, e = 1.602x10-19 C, N =...
Draw the Born-Haber Cycle with these values and calculate lattice energy. Problem 1: Label each reaction listed below for the Born-Haber cycle in the formation of Cao lattice and calculate the lattice energy of Cal given the following information. AH KD) Ca(s) + Ca(8) 193 Calg) - Cat (8) + e 590 Cat (8) - Cat (8) + e- 2 O(g) + O2(g) O(8) + e- O (8) -141 O (8) + e- O (8) 878 Ca(s) + O2(g) →...
7. Use the Born Haber cycle and the given information to determine the net energy change (in kJ/mol) that takes place in the formation of KF(s) from the elements: Ks) + F2@KFS) Heat of sublimation of K = 89.2 kJ/mol Bond dissociation energy for F2 = 158 kJ/mol Lattice Energy of KF = 821 kJ/mol Eca for F = -328 kJ/mol E; for K = 418.8 kJ/mol
Using the data given below, sketch a Born-Haber cycle for the formation of BaC2(s) and insert the various equations and energy values into the individual steps of your cycle Sublimation energy for Ba(s) +180 kJmol1 Electron affinity for Cl(g)-346 kJmol1 First ionization energy for Ba(g)-+514 kJmol1 Bond dissociation energy for Clh(g) +243 kJmol Enthalpy of formation of BaCl2: Ba(s) + Ch(g) BaCh(s)--610 kJmol Lattice energy. Ba2+(g) + 2Cl.(g) → BaCl2(s)--2075 kJmol-1 Calculate the second ionization energy for Ba+(g) → Ba2+(g)...
Construct a Born-Haber cycle and calculate the lattice energy of CaC2 (s). Note that this solid contains the diatomic ion C22–.Useful Information:?H°f (CaC2(s)) ?Hsub (Ca (s)) ?Hsub (C (s)) Bond dissociation energy of C2 (g) = +614 kJ/molFirst ionization energy of Ca (g) = +590 kJ/mol Second ionization energy of Ca (g) = +1143 kJ/mol First electron affinity of C2 (g) = –315 kJ/mol Second electronaffinity of C2 (g) = +410 kJ/mol= –60 kJ/mol = +178 kJ/mol = +717 kJ/mol