Calculate the enthalpies of formation, ΔHfo, of the following group 1 fluoride compounds from their elements using the Born–Haber cycle.
Calculate the enthalpies of formation, ΔHfo, of the following group 1 fluoride compounds from their elements...
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
4) Calculate the lattice enthalpy for calcium fluoride using the Born-Haber cycle method, using the provided table. (Show all your work; 2 points) Enthalpies, AH/(kJ mol) +192 Process Sublimation of Ca(s) Ionization of Ca(g) Dissociation of F2(g) Electron gain by F(g) Formation of CaF (s) +1735 to Ca(ag +157 -328 -1220
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
Consider the following information. • The lattice energy of NaCl is AHlattice = –788 kJ/mol. • The enthalpy of sublimation of Na is AHsub = 107.5 kJ/mol. • The first ionization energy of Na is IE1 = 496 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for NaCl(s). AH= kJ/mol
Knowing the enthalpy of formation of calcium fluoride is -1228 KJ / mol, the enthalpy of the sublimation of calcium is 168kj/mole, the bond enthalpy of fluorine is 155kj/mole, the electron affinity of fluorine is -328 kj/mole, the first ionization enthalpy of calcium is 590kj/mole and the second ionization enthaply is 1145kj/mole, calculate the lattice enthalpy of calcium fluoride.
2. Use the following data to calculate the lattice energy (U) of NaCl(s) from sodium me chlorine: Enthalpy of formation (4H) for NaCl(s) - -411 kJ/mol Enthalpy of sublimation (4Hub) of Na 107.3 kJ/mol The first ionization energy of Na (E,)-495.8 kJ/mol The bond dissociation energy (D) of Clh- 243 kJ/mol The electron affinity of Cl (Eea)- 348.6 kJ/mol.
Calculate the lattice energy for LiF(s) given the following: sublimation energy for Li(s) = +166 KJ/mol delta Hf for F(g) = +77 KJ/mol first ionization energy of Li(g) = +520 KJ/mol electron affinity of F(g) = -328 KJ/mol enthalpy of formation of LiF(s) = -617 KJ/mol
Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2 -1228 kJ/mol Heat of sublimation of Ca 177.8 kJ/mol Bond dissociation energy of F2 159 kJ/mol First ionization energy of Ca 589.8 kJ/mol Second ionization energy of Ca 1145.4 kJ/mol . Electron affinity of F -328 kJ/mot [ Answer : -2644 KJİ I
Sr2+ (8) + 2e +216) 6 Sr2+ (g) + 2e + 12 (g) 7 Sr2+ (g) + 211- (e) 5 Sr1+ (g) + 1e + 12 (8) 4 Srie) + 12 (8) 3 Sre) + 12 (s) 8 2 Sris) + 12 (5) 1 Sr12(s) Using the Born Haber cycle in the previous question, and the energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549...
need help with (CsCl) ICO Given the following enthalpies, cal Enthalpies (kJ/mol): howing enthalpies, calculate the lattice energy of Nal and CsCls), respectively. Inal(s)] = -288; AH (Na) = 107; IE(Na) = 496: AH.(1.) = 62: D(I—I) = 149, EAT) = -295; SCI(8)] = -443; AH.(Cs) = 78: IE(Cs) = 376; D(CI_CI) = 244; EA[Cl] = -349. Na (s) + + Iz (9) Hfy Na I (3) Na(9) I (9) Nat(9) I- -288 = 1074490 +33 + 149 -295 -288x=4135...