Using the "unit conversion method", derive an equation to calculate the heat produced from the HCl-NaOH reaction
To calculate the heat produced from the HCl-NaOH reaction, we can use the following equation:
Heat produced = moles of limiting reactant × ΔH of reaction
The "unit conversion method" involves converting the given quantities into moles and then using the stoichiometric coefficients from the balanced chemical equation to determine the moles of the limiting reactant.
Let's assume we have the balanced chemical equation:
HCl + NaOH → NaCl + H2O
Now, let's derive the equation step by step:
Convert the given quantities of reactants into moles.
Convert the mass of HCl to moles: Moles of HCl = Mass of HCl / Molar mass of HCl
Convert the volume of NaOH to moles (if a solution is provided): Moles of NaOH = Volume of NaOH (in liters) × Molarity of NaOH
Determine the limiting reactant. Compare the moles of HCl and NaOH calculated in step 1 using the stoichiometric coefficients from the balanced chemical equation. The reactant with fewer moles is the limiting reactant.
Determine the moles of the other reactant that react with the limiting reactant based on the stoichiometry of the balanced chemical equation.
Calculate the heat produced using the equation: Heat produced = Moles of limiting reactant × ΔH of reaction
The value of ΔH of reaction represents the enthalpy change associated with the reaction, which can be positive (endothermic) or negative (exothermic).
It's important to note that the specific values of molar masses, volumes, molarity, and ΔH of reaction will depend on the particular reaction being considered.
Using the "unit conversion method", derive an equation to calculate the heat produced from the HCl-NaOH...
1 mol 1. Using dimensional analysis, calculate the number of moles of NaOH (nou) used in reaction #1 (show your work): NaOH (mol) = mnao (9) Where non is MM NaOH (9) the number of moles NaOH, mNaOH is the mass of sodium hydroxide used, and MMNOH is the molar mass of sodium hydroxide. 2. Using the density of water (d != 1.000.), calculate the mass of the 50.0 g water used in reaction #1 using: mwater = Vwater X...
HCl and NaOH react according to the following equation: HCl (aq) + NaOH → Na+(aq) + Cl-(aq) + H2O(l) In a coffee cup calorimeter, 50mL of 2.00 M HCl was combined with 50mL of 2.05 M NaOH. The temperature of the solution rises from 22 degree C to 36 degrees C. What is the enthalpy change for the reaction (delta H rxn)? What is the molar enthalpy for the reaction? Given: The heat capacity of the calorimeter (Cc) is 14.0...
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCI + NaOH → H20+ NaCl To calculate the approximate enthalpy change for this reaction using q = m. C-AT, what value should the student give to C in the equation? The student must use the heat of formation of water. The student must use the heat of formation of...
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCI + NaOH + H2O + NaCl To calculate the approximate enthalpy change for this reaction using q = m.C•AT, what value should the student give to C in the equation ? The student must use the heat of formation of water. The student must use the heat of formation...
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCI + NaOH + H2O + Naci To calculate the approximate enthalpy change for this reaction using q = m-C-AT, what value should the student give to C in the equation? The student must use the heat of formation of water. The student must use the heat of formation of...
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCI + NaOH + H2O + NaCl To calculate the approximate enthalpy change for this reaction using q = m.C.AT, what value should the student give to C in the equation ? The student must use the heat of formation of water. The student must use the heat of formation...
Lab 9 Heat of Reaction
OBJECTIVE:
To experimentally determine the heat of reaction for two
exothermic reactions.
DISCUSSION:
The heat given off or gained in a reaction is called the heat
of reaction (∆?????????).
A reaction that releases heat is known as an exothermic
reaction; an endothermic reaction
is one that absorbs heat.
The heat of the reaction corresponds to one mole of the
reactant and is expressed in
kilocalories per mole of reactant or in kilojoules per mole of...
Heat of Neutralization: Determine DeltaT in (C) and calculate the total number of calories produced. the density of the 0.500 M NaCl produced is 1.02 g/mL, and its specific heat is 0.960 cal/g x C. Calculate the heat of neutralization per mole of water produced. Volume of HCl: 50.0 mL Concentration of HCl: 1.00 M Volume of NaOH: 50.0 mL Concentration of NaOH: 1.00 M Initial temperature: 29.0 C Final Temp 26.8 C
• Ina neutralization reaction, NaOH reacted with HC at S1.OS'c to produce tog of Nacl solution at 54'C. Calculate (a) the heat of solution in Joules. (s= 4.184 1/CSS Two 100 ml solutions of NaOH and HCl both have a concentration of IM. When they are mixed in. Styrofoam cup, the temperature raised from 20°C to 35.7°C. What is the heat released (e)? The temperature of NaOH solution is 13°C, and that of HCl solution is also 13'c. When they...
C. ΔH for Reaction of HCl(aq) and NaOH(s): Volume of HCl: .05 L Volume of water: .05 L Volume total: .1 L Molarity of HCl: 2.08 M Mass of NaOH: 3.93 g ΔT for reaction C: 19°C 1. Calculate the number of moles of NaOH 2. Using NaOH as the limiting reagent, calculate the molarity of the resulting sodium chloride solution. 3. Calculate the value (calories) for the heat of reaction. 4. Calculate the ΔH for this reaction. 5. Is...