The gravity of a black hole is so strong that not even light can escape from within its surface or “event horizon.” Even outside that surface, enormous energies are needed to escape. Suppose that you are 11.0 km away from the center of a black hole that has a mass of 1.00x1031 kg. If your mass is 72.0 kg, how much do you weigh?
NOTE: The answer im getting is 3.968*10^14 N. However, it is not accepting the (*10^14 on the website) I tried without and I still don't get why my answer is wrong.
The gravity of a black hole is so strong that not even light can escape from...
Nothing can escape the event horizon of a black hole, not even light. You can think of the event horizon as being the distance from a black hole at which the escape speed is the speed of light, 3.00 × 108 m/s, making all escape impossible. Part A What is the radius of the event horizon for a black hole with a mass 6.0 times the mass of the sun? This distance is called the Schwarzschild radius.
Now we consider a black hole of the same mass as the Sun: Mbh 2x 1030 kg. (a) (2 marks) Show that if you are launching a rocket with velocity v upwards from a pl M, you can only escape the planet's gravity if you start from a radius r > 2GM/ t of mass Hint: Use Newtonian mechanics. What if your rocket is acutally a beam of light? If we forget about relativity for a minute, we can put...
Now we consider a black hole of the same mass as the Sun: Mbh 2 x 1050 k (a) (2 marks) Show that if you are launching a rocket with velocity v upwards from a planet of mass M, you can only escape the planet's gravity if you start from a radius r > 2GM/v2 Hint: Use Newtonian mechanics What if your rocket is acutally a beam of light? If we forget about relativity for a minute, we can put...