Given that z is a standard normal random variable,
compute the following probabilities (to 4 decimals).
Answer :
(a). P(-1.91 ≤ z ≤ 0.41)
= p( z ≤ 0.41 ) - p( z ≤ -0.91 )
=> using the standard normal z table
= 0.6591 - 0.1814
= 0.4777
P(-1.91 ≤ z ≤ 0.41) = 0.4777
(b). P(0.55 ≤ z ≤ 1.26)
= p( z ≤ 1.26 ) - p( z ≤ 0.55 )
=> using the standard normal z table
= 0.8961 - 0.7088
= 0.1873
P(0.55 ≤ z ≤ 1.26) = 0.1873
(c). P(-1.75 ≤ z ≤ -1.08)
= p( z ≤ -1.08 ) - p( z ≤ -1.75 )
=> using the standard normal z table
= 0.1400 - 0.0400
= 0.1000
P(-1.75 ≤ z ≤ -1.08) = 0.1000
Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals)....
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