Answer:
Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals).
a.P(-1.98<z< .49) = P( z <0.49) –P( z <-1.98)
= 0.6879 - 0.0239
=0.6640
b.P(.52 < z < 1.22) = P( z <1.22) – P( z (0.52)
=0.8888 - 0.6985
=0.1903
c. P(-1.75 < z < -1.04) = P( z <-1.04) – P( z < -1.75)
=0.1492 -0.0401
=0.1091
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