20.Suppose x is normally distributed with mean 2,825 and standard deviation 250.
Find P(2,700 ≤ x ≤ 3,200).
Solution :
Given that ,
mean = = 2825
standard deviation = = 250
P( 2700 x 3200 )
= P[( 2700 -2825/ 250) (x - ) / (3200-2825 /250 ) ]
= P(-0.5 z 1.5 )
= P(z 1.5) - P(z -0.5)
Using z table,
=0.9332 -0.3085
=0.6247
probability=0.6247
20.Suppose x is normally distributed with mean 2,825 and standard deviation 250. Find P(2,700 ≤ x...
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