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20.Suppose x is normally distributed with mean 2,825 and standard deviation 250. Find P(2,700 ≤ x...

20.Suppose x is normally distributed with mean 2,825 and standard deviation 250.

Find P(2,700 ≤ x ≤ 3,200).

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Answer #1

Solution :

Given that ,

mean = = 2825

standard deviation = = 250

P( 2700  x 3200 )

= P[( 2700 -2825/ 250) (x - ) / (3200-2825 /250 ) ]

= P(-0.5 z 1.5 )

= P(z 1.5) - P(z -0.5)

Using z table,   

=0.9332 -0.3085

=0.6247

probability=0.6247

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