Question

The sulfuric acid and sodium hydroxide need to be mixed in the correct stoichiometric ratios. They are both the same concentration so the volume ratio will match the stoichiometric ratio. If you want a total of 100.0 mL what volume of sulfuric acid will you add to the calorimeter? Answer in mL.

Answer 1

volume of sulfuric acid = 33.3 mL

Explanation

The balanced reaction is : H₂SO₄ (aq) + 2 NaOH (aq) Na₂SO₄ (aq) + 2 H₂O (l)

Given : concentration of H₂SO₄ = concentration of NaOH

Let concentration of H₂SO₄ = concentration of NaOH = 1 M

Let volume H₂SO₄ required = x mL

then, volume NaOH required = total volume - volume H₂SO₄ required

volume NaOH required = 100.0 mL - x mL

moles H₂SO₄ = (concentration of H₂SO₄) * (volume H₂SO₄ required)

moles H₂SO₄ = (1 M) * (x mL)

moles H₂SO₄ = x mmol

moles NaOH required = 2 * (moles H₂SO₄)

moles NaOH required = 2 * (x mmol)

moles NaOH required = 2x mmol

volume NaOH required = (moles NaOH required) / (concentration NaOH)

volume NaOH required = (2x mmol) / (1 M)

volume NaOH required = 2x mL

Substituting the value of volume NaOH required from above

100.0 mL - x mL = 2x mL

100.0 mL = 3x mL

x = (100.0 mL) / (3)

x = 33.3 mL

volume H₂SO₄ required = x mL = 33.3 mL