The net force exerted on a particle acts in the +x direction. Its magnitude increases linearly from zero at x = 0, to 22.0 N at x = 3.5 m . It remains constant at 22.0 N from x = 3.5 m to x = 8.0 m , and then decreases linearly to zero at x = 13.0 m . A) Determine the work done to move the particle from x = 0 to x = 13.0 m graphically by determining the area under the F x vs. x graph
The graph of the Force vs displacement for the given problem is shown below:
The area of a trapezium is given by
which gives us
The net force exerted on a particle acts in the +x direction. Its magnitude increases linearly...
The magnitude of the net force exerted in the x direction on a 3.90-kg particle varies in time as shown in the figure below. (a) Find the impulse of the force over the 5.00-s time interval. I = ? (N · s) (b) Find the final velocity the particle attains if it is originally at rest. Vf = ? (m/s) (c) Find its final velocity if its original velocity is -3.10 i m/s. Vf = ? (m/s) (d) Find the...
A single, nonconstant force acts in the +?+x direction on an 5.06 kg5.06 kg object that is constrained to move along the ?x‑axis. As a result, the object's position as a function of time is ?(?)=?+??2+??4?=7.38 m?=4.57 m/s2?=0.478 m/s4x(t)=A+Bt2+Ct4A=7.38 mB=4.57 m/s2C=0.478 m/s4 How much work is done by this force from ?=0 st=0 s to ?=2.34 s?
46 and 47 Please, 46. Determine the magnitude and direction of the electric force exerted by a 25-nC charged particle located at the origin of a Cartesian coordinate system on a 20-nC charged particle located at (2.0 m, 2.0 m). Draw a diagram illustrating the vari- ous quantities in your calculation. 47. The electric force between two identical positively charged ions is 3.7 X 109 N when they are 0.50 nm apart. How many electrons are missing from each of...
Exercises 1. Suppose a force acts on a 4.00 kg object in the x-direction. The force varies with time and is given by F(t)12.0t3 - 8.00 N. At t -0, the object has a velocity of 3.00 m/s in the positive x-direction. Use the impulse-momentum theorem to find the object's velocity after 2.00 s. 2. In a lab experiment, a spring gun projects a metal sphere. The sphere leaves the spring gun with a velocity of 3.00 m/s in the...
A conservative force F(x) acts on a 1.7 kg particle that moves along an x axis. The potential energy U(x) associated with F(x) is graphed in the figure. When the particle is atx-2.0 m, its velocity is -1.7 m/s. (a) What is F(x) at this position, including sign? Between what positions on the (b) left and (c) right does the particle move? (d) what is its particle's speed at x = 7.0 m? x (m) 0 10 15 0 -5...
Question 3 A single force acts on a 1.2 kg particle-like object in such a way that the position of the object as a function of time is given by x = 1.0t - 3.22 + 3.5+, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 5.9 s. Number Units the tolerance is +/-2%
A particle is subject to a force Fx that varies with position as shown in the following figure. F (N) 3 2 1 x (m) 0 2 4 6 8 10 12 14 16 (a) Find the work done by the force on the particle as it moves from x = 0 to x = 2.00 m. (b) Find the work done by the force on the particle as it moves from x = 5.00 m to x = 7.00...
force Fx acts on a particle that has a mass of 2 kg. The force is related to the position x of the particle by the formula F 3, where C-0.5 if x is in meters and Fy is in Newton (a)What are the SI units of C? (Use the following as necessary: N and m.) (b) Find the work Wdone by this force as the partidle moves from x - 2.8 m to x - 1.6 m (C) At...
Find the direction and magnitude of the net electrostatic force exerted on the point charge q2 in the figure below. Let q = +2.7 µC and d = 33cm.Direction° (from the x-axis, which points to the rightMagnitude_______ N
A single conservative force acts on a 4.50-kg particle within a system due to its interaction with the rest of the system. The equation Fx = 2x + 4 describes the force, where Fx is in newtons and x is in meters. As the particle moves along the x axis from x = 1.10 m to x = 6.55 m, calculate the following. (a) the work done by this force on the particle J (b) the change in the potential...