Question

In Java. Make a multi dimension array of 2 rows and 5 columns. Put 10 random whole numbers into the multi dimension array. Find the smallest number in the array. Search the array for odd numbers and display them along with their position in the array.

Answer 1

Random2DArray.java

import java.util.Random;

public class Random2DArray {

public static void main(String[] args) {

int arr[][] = new int[2][5];

Random r = new Random();

for(int i=0;i<arr.length;i++) {

for(int j=0;j<arr[i].length;j++) {

arr[i][j] = r.nextInt(1000) + 1;

}

}

int min = arr[0][0];

for(int i=0;i<arr.length;i++) {

for(int j=0;j<arr[i].length;j++) {

if(min > arr[i][j]) {

min = arr[i][j];

}

}

}

System.out.println("Smallest number is "+min);

System.out.println("Odd numbers are:");

for(int i=0;i<arr.length;i++) {

for(int j=0;j<arr[i].length;j++) {

if(arr[i][j] % 2 != 0) {

System.out.println("arr["+i+"]["+j+"] = "+arr[i][j]);

}

}

}

}

}

Output:

Smallest number is 34
Odd numbers are:
arr[0][1] = 883
arr[1][2] = 305
arr[1][3] = 143