Question

How many grams of solute are present in 415 mL of 0.510 M KBr?

mass of solute:

Answer 1

molarity = number of moles of KBr / volume of solution in L

0.510 = number of moles / 0.415

number of moles of KBr = 0.212 mole

number of moles of KBr = mass of KBr / molar mass of KBr

0.212 mole = mass of KBr / 119.002 g/mol

mass of KBr = 25.2 g

Therefore, the mass of KBr = 25.2 g